The only sidebets I really play are 8 and 9. I believe they have the highest probability of being rolled next to a 7. Every now and then, I’ll bet on the hard numbers of the point. So if the point is 6… I’ll bet on the hard six the entire time because there is a 1 and 3 chance that the next 6 rolled will be the hard 6. (combos of 5,1 4,2 and 3,3).

I am new to gambling and I’ve never played craps before and I was wondering what a side bet was? I’ve only seen the craps table and have watched people play but I’ve never had the courage to actually play it myself.

I am very random with my side bets, but then again so are the dice.  I just like to throw out a little extra to raise my odds of winning something.  This is not a science, but it sure is fun.

The one that I have been playing recently is the Four Rolls no Seven side bet. It’s pretty easy to figure this one out. All you have to do is roll four times in a row by avoiding a 7.

onetime77 there is a 1 in 5 chance of rolling a hard 6 there are 36 possible outcomes and there are 5 ways to make a six 5-1,4-2,3-3,2-4,1-5 not 3 ways each dice has its own chance of rolling that number ie 6x6 is 36 you should always base your probablity on 36 possible combos i saw a chart in a book once that makes it very easy to remember if i find it again i will post it for you but here was the basics of it

Number     Possible ways to roll
2           1 (1-1)
3           2 (2-1,1-2)
4           3 (3-1,2-2,1-3)
5           4(4-1,3-2,2-3,1-4)
6           5(5-1,4-2,3-3,2-4,1-5)
7           6(6-1,5-2,4-3,3-4,2-5,1-6)
8           5(6-2,5-3,4-4,3-5,2-6)
9           4(6-3,5-4,4-5,3-6)
10           3(6-4,5-5,4-6)
11           2(6-5,5-6)
12           1(6-6)

hope this helps some

onetime77 - 11 January 2009 11:58 AM

The only sidebets I really play are 8 and 9. I believe they have the highest probability of being rolled next to a 7. Every now and then, I’ll bet on the hard numbers of the point. So if the point is 6… I’ll bet on the hard six the entire time because there is a 1 and 3 chance that the next 6 rolled will be the hard 6. (combos of 5,1 4,2 and 3,3).

Actually, it is the six and eight that are the most likely numbers behind the seven.

You are mistaken about the hard six, because 5,1 and 4,2 can occur two ways, whereas 3,3 can only occur one way, so only one of five sixes is expected to be “hard”. Also, of course, the hardways lose on a seven, as well. So:

3,3 win
4,2 2,4 5,1 1,5 1,6 6,1 2,5 5,2 3,4 4,3 all lose

So, ten ways to lose, one to win. The house pays 9 for a win, so, on average, you expect to lose one unit ten times and win nine units once. a loss of one unit per eleven bets, or a 9.09% house advantage. Compare that to 1.4% on the pass line. On the other hand, you can make hardway bets for a dollar at many tables and, because of the 9:1 payoff, it only takes one extra win out of 99 bets to come out ahead (barely). One way that I “toke” the dealers is to make a “two-way” hardway bet, $1 for myself and $1 for the dealers. If you win that bet, the dealers get $10 and it never hurts to have the dealers like you. >:-) they will appreciate it even if the bet loses.

Cheers,
Alan Shank

Thanks Shank! Awesome reply!

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